The coach of a cricket team buys 7 bats and 6 balls for Rs 3800. Later, she buys 3 bats and 5 balls for Rs 1750. Find the cost of each bat and each ball.

The coach of a cricket team buys 7 bats and 6 balls for Rs 3800. Later, she buys 3 bats and 5 balls for Rs 1750. Find the cost of each bat and each ball.

Let        cost of each bat      =  Rs x

Cost of each ball      = Rs y

Given that coach of a cricket team buys 7 bats and 6 balls for Rs 3800.

So that                       7x + 6y          = 3800

6y        = 3800 – 7x

Divide by 6 we get

y          = (3800 – 7x) /6         … (1)

Given that she buys 3 bats and 5 balls for Rs 1750.so that

3x + 5y = 1750

Plug the value of y

3x + 5 ((3800 – 7x) /6)        = 1750

Multiply by 6 we get

18 x  + 19000 – 35 x            = 10500

-17x    =10500 - 19000

-17x    = -8500

x         = - 8500 / - 17

x         =  500

Plug this value in equation first we get

y          = ( 3800 – 7 * 500) / 6

y          = 300/6

y          = 50

Hence cost of each bat = Rs 500 and cost of each balls is Rs 50