Question 9:
A system has two charges qA
= 2.5 × 10−7 C and qB = −2.5 × 10−7 C located
at points A: (0, 0, − 15 cm) and B: (0, 0, + 15 cm), respectively. What are the
total charge and electric dipole moment of the system?
Solution:
we have tio
Given that
qA = 2.5 ×
10−7 C
qB = −2.5 ×
10−7 C
A: (0, 0, − 15 cm)
B: (0, 0, + 15 cm),
The value of x and y
coordinate is zero in both points A and B
So both points are in
straight line
And the distance
between both points is = 15 – (-15) = 30
cm = 0.30 m
Total charge of the
system will
q = qA + qB
= 2.5 × 107
C − 2.5 × 10−7 C
= 0
The formula of electric
dipole moment of the system
p = charge × d
= qA × d
= 2.5 × 10−7
× 0.3
= 7.5 × 10−8
C m
In this problem negative charge is along positive z-axis
Answer
7.5 × 10−8 C
m along positive z−axis.
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