6. In
Fig. 5.10, if AC = BD, then prove that AB = CD.
From
the above figure we get that
AC = AB +
BC
BD = BC + CD
It
is given that AC = BD
Plug
the value of AC we get
AB + BC = BC + CD …
(1)
According
to Euclid’s axiom,when equals are subtracted from equals, the remainders
are
also equal.
Subtracting
BC from both side in equation (1), we get
AB + BC − BC = BC
+ CD − BC
AB = CD
Hence
proved
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