NCERT Solutions, CBSE Sample Papers and Syllabus for Class 9 to 12 : Question 4.23: The rate constant for the decomposition of hydrocarbons is 2.418 × 10−5 s−1 at 546 K. If the energy of activation is 179.9 kJ/mol

Showing posts with label Question 4.23: The rate constant for the decomposition of hydrocarbons is 2.418 × 10−5 s−1 at 546 K. If the energy of activation is 179.9 kJ/mol. Show all posts

Showing posts with label Question 4.23: The rate constant for the decomposition of hydrocarbons is 2.418 × 10−5 s−1 at 546 K. If the energy of activation is 179.9 kJ/mol. Show all posts

Monday, 10 June 2013

Question 4.23: The rate constant for the decomposition of hydrocarbons is 2.418 × 10−5 s−1 at 546 K. If the energy of activation is 179.9 kJ/mol, what will be the value of pre-exponential factor.

Question 4.23: The rate constant for the decomposition of hydrocarbons is 2.418 × 10 −5 s −1 at 546 K. If the energy of activation is 179...