Mass of component in
first solution = 25% of 300 gram =
25*300/100 = 75 gram
Mass of component in
second solution = 40 % of 400 gram =
40*400/100 = 160 gram
Total mass of solution =
300+400 = 700 gram
Total mass of
component = 75+ 160 = 235 grams
Mass % of final
solution = mass of component * 100 / total mass
=235*100/700 = 33.5%
Total of % is always 100
So % of water in
solution = 100 – 33.5 = 66.5 %
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Deletewhat mass of water must 25 gram of CuSO4.5H2O be dissolved to obtain an 8% solution of CuSO4?
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