Wednesday, 13 February 2013

A solution is obtained by mixing 300 g of 25% solution and 400 g of 40% solution by mass. Calculate the mass percentage of the resulting solution.

Mass of component in first solution = 25% of 300 gram  = 25*300/100 = 75 gram
Mass of component in second solution   = 40 % of 400 gram = 40*400/100 = 160 gram

Total mass of solution = 300+400 = 700 gram
Total mass of component  = 75+ 160  = 235 grams

Mass % of final solution     = mass of component * 100 / total mass
                                         =235*100/700  = 33.5%
Total of % is always 100
So % of water in solution = 100 – 33.5  = 66.5 % 

3 comments:

  1. please send your problem , i will reply with in 24 hours

    ReplyDelete
    Replies
    1. One gram of an alloy of aluminium and magnesium when heated with excess of dilute HCl forms magnesium chloride aluminium Chloride and hydrogen evolve hydrogen collected at zero degree celsius has a volume of 1.12 litres at 1 ATM pressure calculate the composition of alloy ..... Please reply as soon as possible

      Delete
  2. what mass of water must 25 gram of CuSO4.5H2O be dissolved to obtain an 8% solution of CuSO4?

    ReplyDelete