Q1:
Check whether the following are quadratic equations:
(i)
(x + 1)2 = 2(x – 3)
(ii)
x2 – 2x = (–2) (3 – x)
(iii)
(x – 2)(x + 1) = (x – 1)(x + 3)
(iv)
(x – 3)(2x +1) = x(x + 5)
(v)
(2x – 1)(x – 3) = (x + 5)(x – 1)
(vi)
x2 + 3x + 1 = (x – 2)2
Answer:
(i)
(x + 1)2 = 2(x – 3)
use
formula (a+b)2=a2 +2ab +b2
or,
x2 + 2x + 1 = 3x – 6
subtract
3x and add 6 both side we get
or,
x2 + 2x -3x + 1 + 6 = 0
or,
x2 - x + 7 = 0
Above
equation is in form of ax2
+ bx + c = 0, so it is a quadratic equation.
(ii)
x2 – 2x = (–2) (3 – x)
or,
x2– 2x = –6 + 2x
or,
x2– 2x - 2x + 6 = 0
or,
x2– 4x + 6 = 0
Above
equation is in form of ax2
+ bx + c = 0, it is a quadratic equation.
(iii)
(x – 2)(x + 1) = (x – 1)(x + 3)
Open
the bracket
or,
x2 + x -2x - 2 = x2 + 3x -x -3
simplify
it we get
or,
x2 - x - 2 = x2 + 2x - 3
or,
x2 - x - 2 - x2 - 2x + 3 = 0
or,
-3x + 1 = 0
change
the sign
or,
3x - 1 = 0
Above
equation is NOT in form of ax2
+ bx + c = 0, it is NOT a quadratic equation.
(iv)
(x – 3)(2x +1) = x(x + 5)
Open
the bracket
or,
2x2 + x - 6x - 3 = x2 + 5x
Simplify
it
or,
2x2 - 5x - 3 - x2 - 5x = 0
subtract
the values
or,
x2- 10x - 3 = 0
Above
equation is in form of ax2
+ bx + c = 0, it is a quadratic equation.
(v)
(2x – 1)(x – 3) = (x + 5)(x – 1)
Open
the bracket
or,
2x2 - 6x - 1x + 3 = x2 - 1x + 5x - 5
simplify
it
or,
2x2 - 7x + 3 = x2+ 4x - 5
subtract
the values
or,
2x2 - 7x + 3 - x2 - 4x + 5 = 0
simplify
it again
or,
x2 - 11x + 8 = 0
Above
equation is in form of ax2
+ bx + c = 0, it is a quadratic equation.
(vi)
x2 + 3x + 1 = (x – 2)2
use
formula (a-b)2=a2 -2ab +b2
or,
x2 + 3x + 1 = x2 + 4 - 4x
subtract
the value
or,
x2 + 3x + 1 - x2 - 4 + 4x =0
simplify
it
or,
7x - 3 = 0
Above
equation is NOT in form of ax2
+ bx + c = 0, it is NOT a quadratic equation.
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