Find a
quadratic polynomial each with the given numbers as the sum and product of its
zeroes respectively.
(i)1/4 , -1 (ii) √2 , 1/3 (iii) 0, √5 (iv)
1,1 (v) -1/4 ,1/4 (vi) 4,1
Solution
(i)1/4 , -1
Now formula of
quadratic equation is
Plug the value in formula we
get
X2 –(1/4)x -1 = 0
Multiply by 4 to remove
denominator we get
4x2 - x -4 = 0
(ii) √2 , 1/3
Now formula of quadratic equation is
Plug the value in formula we
get
x2 –(√2)x +
1/3 = 0
Multiply by 3 to remove
denominator we get
3x2 - 3√2 x +
1 = 0
(iii) 0, √5
Now formula of
quadratic equation is
Plug the value in formula we
get
x2 –(0)x + √5 = 0
simplify it we get
x2 + √5 = 0
(iv) 1,1
Now formula of
quadratic equation is
Plug the value in formula we
get
x2 –(1)x +
1 = 0
simplify it we get
x2 - x +
1 = 0
(v) -1/4 ,1/4
Now formula of
quadratic equation is
Plug the value in formula we
get
x2 –(-1/4)x +
1/4 = 0
multiply by 4 we get
4x2 + x +
1 = 0
(vi) 4,1
Now formula of
quadratic equation is
Plug the value in formula we
get
x2 –(4)x + 1 = 0
x2
–4x + 1 = 0
But according to the question we are asked of find a quadratic polynomial then why are we applying the formula of finding a quadratic equation ?????? Is there any difference between this????
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