Half the perimeter of a rectangular garden, whose length is 4 m more than its width, is 36 m. Find the dimensions of the garden.

Half the perimeter of a rectangular garden, whose length is 4 m more than its width, is 36 m. Find the dimensions of the garden.

Let length of rectangle        = x m

With of the rectangle           = y m

Given that whose length is 4 m more than its width

so  that

x          = 4 + y

plug  y = -18 , 0, and 18 we get

x          = 4 - 18           = -14

x          = 4 +0             =  0

x          = 4 + 18          = 22

X	-14	0	22
y	-18	0	18

Given that Half of the perimeter of the rectangle is 36 m so

Formula of perimeter of the rectangle     = 2(x+y)

Half of perimeter of rectangle                    = (1/2)*2(x + y)          =  x + y    

So our equation will

x + y  = 36

Subtract y both side we get 

X        = 36 – y

Plug  y = 36 ,18 and 0 we get

X         = 36 – 36        = 0

X         = 36 – 18        = 18

X         = 36 – 36        = 0

X	0	18	36
y	36	18	0

 

Hence length of garden = 20 m

Width of garden = 16 m