Half the perimeter of a rectangular
garden, whose length is 4 m more than its width, is 36 m. Find the dimensions
of the garden.
Let length of rectangle =
x m
With of the rectangle =
y m
Given that whose length is 4 m more than its width
so that
x = 4 + y
plug y = -18 , 0,
and 18 we get
x = 4 - 18
= -14
x = 4 +0 = 0
x = 4 +
18 =
22
|
X
|
-14
|
0
|
22
|
|
y
|
-18
|
0
|
18
|
Given that Half of the perimeter of the rectangle is 36 m
so
Formula of perimeter of the rectangle = 2(x+y)
Half of perimeter of rectangle = (1/2)*2(x + y) = x + y
So our equation will
x
+ y = 36
Subtract y both side we get
X = 36 – y
Plug y = 36 ,18 and
0 we get
X = 36 – 36
= 0
X = 36 – 18 = 18
X = 36 – 36 = 0
|
X
|
0
|
18
|
36
|
|
y
|
36
|
18
|
0
|
Hence length of garden = 20 m
Width of garden = 16 m
