The coach of a cricket team buys 3 bats and 6 balls for Rs 3900. Later, she buys another bat and 2 more balls of the same kind for Rs 1300. Represent this situation algebraically and geometrically

The coach of a cricket team buys 3 bats and 6 balls for Rs 3900. Later, she buys another bat and 2 more balls of the same kind for Rs 1300. Represent this situation algebraically and geometrically.

Let cost of one bat  = Rs x

Cost of one ball      = Rs y

 3 bats and 6 balls for Rs 3900 So that

3 x + 6y = 3900                     … (1)

Divide complete equation by 3 we get

x+ 2y = 1300                       

Subtract 2y both side we get

x = 1300 – 2y  

 Plug y = - 1300, 0 and 1300  we get

x = 1300 – 2 ( - 1300 )   = 1300 + 2600   =  3900

x= 1300 -2(0)                = 1300 -0          = 1300

x= 1300 – 2(1300)         = 1300 – 2600   = - 1300  

X	3900	1300	-1300
y	-1300	0	1300

Given that  she buys another bat and 2 more balls of the same kind for Rs 1300

So we get

x  + 2 y = 1300                      … (2)

Subtract 2y both side we get

x          = 1300 – 2y

 Plug y = - 1300, 0 and 1300  we get

x        = 1300 – 2 ( - 1300 )              = 1300  +  2600        =  3900

x         = 1300 – 2 ( 0 )                     = 1300 - 0                = 1300

x         = 1300 – 2(1300)                  = 1300 – 2600           = -1300

X	3900	1300	-1300
y	-1300	0	1300

                                   

Algebraic representation

3 x + 6 y = 3900                    … (1)

x + 2 y    = 1300                     … (2)