Q1:
Find the roots of the following quadratic equations by factorization:
(i)
x2 – 3x – 10 = 0
(ii)
2x2 + x – 6 = 0
(iii)
√2 x2 + 7 x + 5√2 = 0
(iv)
2x2 – x + 1/8 = 0
(v)
100 x2 – 20x + 1 = 0
Answer:
x2
– 3x – 10 = 0
So
we can write middle term as -3x = -5x + 2x
x2
– 5x + 2x – 10 = 0
x(x - 5) + 2(x - 5) = 0
(x - 5)(x + 2) = 0
x
- 5 = 0 and x + 2 = 0
x
= 5 and x = -2
5 and
-2 are our required root of quadratic
equation.
2x2 + 4x – 3x – 6 = 0
2x(x
+ 2) – 3(x + 2) = 0
(x
+ 2)(2x – 3) = 0
x + 2 = 0 and 2x – 3 = 0
x
= –2 and x = 3/2
–2
and 3/2 are our required root of quadratic
equation.
(iii) √2
x2 + 7x + 5√2 = 0
Similarly
multiply √2 with 5√2 and we get 10
Pairs
of 10 are
1*10
= 10 sum 1+ 10 = 11
So
our required pair is 2 and 5
√2 x2 + 5x + 2x + 5√2 = 0
x
(√2x + 5) + √2(√2x + 5) = 0
(√2x
+ 5)(x + √2) = 0
√2x + 5 = 0 and x + √2 = 0
x
= –5/√2 and x = –√2
–5/√2
and –√2 are our required root of quadratic
equation.
(iv)
2x2 – x + 1/8 = 0
Multiply
by 8 we get
Very nicely thought
ReplyDeleteUnderstandable
Good
Thank you