Question 3:
An
electric bulb is rated 220 V and 100 W. When it is operated on 110 V, the power
consumed will be
Answer (d): 25w
Solution: R=V2/P
= (220)2/100
= 484 Ω
The resistance of the bulb
remains constant
if the supply voltage is reduced to 110 V then
Vʹ=110 V
the power consumed by it is given by the
expression = Vʹ2/R
= (110)2/484
= 25w
Why can't we do it by P=VI ......
ReplyDeleteI have the same doubt
DeleteBecause current changes with change in potential difference but the resistance of the appliance will remain the same
Delete