Question 2:
An electric
lamp of 100 Ω, a toaster of resistance 50 Ω, and a water filter of resistance
500 Ω are connected in parallel to a 220 V source. What is the resistance of an
electric iron connected to the same source that takes as much current as all
three appliances, and what is the current through it?
Solution:
Resistance
of electric lamp (R1) = 100 Ω
Resistance
of toaster (R2) = 50 Ω
Resistance
of water filter (R3) = 500 Ω
Potential
difference of the source, V = 220 V
Since all the resistance are in parallel then
the equivalent resistance
R of the circuit will be
All the
three given appliances are drawing 7.04 A of current.
Therefore, current drawn by an electric iron connected to the same source
of potential 220 V = 7.04 A
Let Rʹ be the resistance of the
electric iron. According to Ohm’s law,
Therefore, the resistance of the electric iron is 31.25 Ω and the current
flowing through it is 7.04 A.
Wow really helpful
ReplyDeleteChal re ran de
DeleteHelpful
DeleteNice one
ReplyDeleteWish I had this website during my 10th.
ReplyDeleteAww of course you do
DeleteHi,he mentioned electric iron also connected.then how can u take only R1,R2,R3 and calculate total resistance of a ckt
ReplyDeleteNo problem. Answer is correct
DeleteThanks
ReplyDeletethanks
ReplyDeleteReally this helped me a lot..
ReplyDeleteThanks a lot
It helps me to understand. I am sure that it helps to everyone.
ReplyDeleteWhy we reciprocal the 16 by 500 and again reciprocal it to 500 bye 16
ReplyDeleteBecause it is connected in parallel. That is y
DeleteBecause it is connected in parallel. That is y
DeleteThanks answer is correct
ReplyDeleteThanks answer is correct
ReplyDelete7.04 is the total current ain't It?? So all three appliances are taking it collectively???
ReplyDeleteThoda aur zyada simple tarika batao
ReplyDeletethanks for this
ReplyDeleteGood
ReplyDelete