At 300 K, 36 g of glucose present in a litre of its solution has an osmotic pressure of 4.98 bar. If the osmotic pressure of the solution is 1.52 bars at the same temperature, what would be its concentration?

At 300 K, 36 g of glucose present in a litre of its solution has an osmotic pressure of 4.98 bar. If the osmotic pressure of the solution is 1.52 bars at the same temperature, what would be its concentration?

Solution:

Mass of glucose, w =36 g

Osmotic pressure, π = 4.98 bar

Temperature, T = 300 K

Volume of solution, V = 1L

Formula of osmotic pressure

Plug the value and solve for R we get

R = π V/(nT) = 4.98 × 180/ (36 × 300)

R = 4.98/ 60  L atm K^-1 mol^{– 1}

Plug the value in second case we get

   

C = π/(RT)

Plug the values we get

 

C = 0.061 M