Friday, 3 May 2013

Boiling point of water at 750 mm Hg is 99.63°C. How much sucrose is to be added to


Boiling point of water at 750 mm Hg is 99.63°C. How much sucrose is to be added to 500 g of water such that it boils at 100°C. Molal elevation constant for water is 0.52 K kg mol−1.
Solution
Normal boiling point of water = 100 C
Elevation of boiling point, ∆Tb = 100 − 99.63  = 0.37
Mass of water w1= 500 g
Molar mass of sucrose (C12H22O11),M2= 11 × 12 + 22 × 1 + 11 × 16 = 342 g mol−1
Molal elevation constant, Kb = 0.52 K kg mol−1
Use the formula 
w2= 121.67 g
Answer   mass of added sucrose = 121.67 g

11 comments:

  1. Should the temperature by converted to kelvin? as it is the SI unit...

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    Replies
    1. No. We only take change in boiling pt.(temperature). So even if we vonveet it and find the change. The valuv remains the same

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  2. Though we convert it to Kelvin we still get the same difference as in Celsius scale. Why did u take 3.37 k instead of 0.37

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  3. The molar mass of sucrose is 330 not 342...
    plz. correct it

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  4. The molar mass of sucrose is 330 not 342...
    plz. correct it

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  5. It's not clear plzz take different method else

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  6. On ncert answer of this question is given 1.86g

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  7. Whish one is correct answer (121.67g or 1.86g) ????

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