Calculate
the mass of ascorbic acid (Vitamin C, C6H8O6) to be dissolved in 75 g of acetic
acid to lower its melting point by 1.5°C. Kf = 3.9 K kg mol−1.
Solution
Given that
Mass of acetic acid, w1 = 75 g
Molar mass of ascorbic acid (C6H8O6),
M2 = 6 × 12 + 8 × 1
+ 6 × 16 = 176 g mol−1
Lowering of melting point, ∆Tf = 1.5 K
Use same formula again we get
w2= 5.08 g
Answer
Required mass o ascorbic acid =5.08
g
Nice thanks a lot
ReplyDeleteIt is wrong
ReplyDeleteIn the question it is 1 Celsius and u took 1 Kelvin in the answer
1.5 celsius is the depression in freezing point which means it's a difference between temperature and it doesn't matter that difference u take in kelvin is different from difference between degree celsius but here according to our requirements we want difference in kelvin .......hope it helps
DeleteYou bloody fool ,^Tb in Kelvin is equal to ^Tb in Celsius
DeleteI am not understand your temperature concept
ReplyDeleteDefine the temp. Concept
ReplyDeleteMany many thanks
ReplyDeleteThanks
ReplyDeleteThank you for your answer
ReplyDeletePerfect procedure as well as answer.
ReplyDeleteThanks for the answer
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ReplyDelete