Friday, 3 May 2013

Calculate the mass of urea (NH2CONH2) required in making 2.5 kg of 0.25 molal aqueous solution.


Calculate the mass of urea (NH2CONH2) required in making 2.5 kg of 0.25 molal aqueous solution.
Solution
Given that
Mass of solution = 2.5 Kg
Molality = 0.25 m
Molar mass of urea (NH2CONH2) =14 + 2 × 1 + 12 + 16 + 14 + 2 × 1 = 60 g mol−1
Let mass of urea (NH2CONH2) = w gram 
Number of moles of urea  = w / 60 = 0.01667 mol
Mass of urea in Kg  = w/1000  = 0.001w kg 
 
Mass  of solvent = total mass  - mass  of solute  = 2.5  - 0.001 w kg
Use the above formula we get 

Cross multiply and solve for  the value of w we get
 

w = 37 g of urea

25 comments:

  1. Given thatMass of solution = 2.5 KgMolality = 0.25 mMolar mass of urea (NH2CONH2) =14 2 × 1 12 16 14 2 × 1 = 60 g mol−1Let mass ofurea (NH2CONH2) = w gramNumber of moles of urea= w / 60 = 0.01667 molMass of urea in Kg= w/1000= 0.001w kgMassof solvent = total mass- massof solute= 2.5- 0.001 w kgUse the above formula we getCross multiply and solve forthe value of w we getw = 37 g of urea

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    Replies
    1. How will we can determine the unit will be gram of the answer

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    2. How will we can determine the unit will be gram of the answer

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  2. Very helpful. I really enjoyed my home work. I complete it on time and I was able to enjoy my rest Holidays����

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  3. How is w/60 equal to 0.0167 mol?????

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  4. This comment has been removed by the author.

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  5. Yes,how w/60 equal to 0.0167mol???

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  6. This comment has been removed by the author.

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  7. This comment has been removed by the author.

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  8. How did we cross multiply n get 37????

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  9. Cross multiply one not understood

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  10. Cross multiply one not understood

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  11. Padai choddd dooo tum loggg agar tumhe yeh answer sahi lgta hhhhhhh Chutiya

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