Calculate
the osmotic pressure in pascals exerted by a solution prepared by dissolving 1.0
g of polymer of molar mass 185,000 in 450 mL of water at 37°C.
Solution
Given that
Mass of polymer = 1.0 g
Molar mass of polymer = 185,000
Volume of water, V = 450 mL = 0.45 L (1 liter = 1000
ml )
Temperature, T = (37 + 273)K = 310 K (add 273 to convert in Kelvin )
Use formula
Number of moles of the polymer = 1/
185000 = 5.41 × 10 – 6
Use formula of osmotic pressure
Plug the values we get
= 30.98 Pa
Answer 30.98 pa
from where this 1000 come while plugging the values.
ReplyDeleteBecause converted from mL to L
DeleteKushal the VALUR OF R IS REPRESENTED AS 8.314×10³ in terms of KPa.
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ReplyDeleteBut my answer was 9.18
ReplyDeleteThank you so much
ReplyDeletethank you ;*
ReplyDeleteThank you so much . .. For your help
ReplyDeletecan't we find the value in atm and convert it into pascal i did it and answer is coming a bit different
ReplyDeleteNo issues u can do that
ReplyDeleteI have putted the value of R as 0.08????
ReplyDeleteThank you so much sir
ReplyDelete