Question 2:
Compute the heat generated while transferring 96000 coulomb of charge in one
hour through a potential difference of 50 V.
Solution:
Given
Charge (Q) =96000C
Time
(t)=1hr=60×60=3600s
Potential
difference V=50volts
Now we know that H= VIt
So we have to calculate I first
As I=Q/t
∴ I=96000/3600=80/3 A
This comment has been removed by the author.
ReplyDeleteYou could have done it directly by H=VQ.
ReplyDeleteyaa that's too correct but this is also write.... There are many methods to do numericals....
DeleteHow can that equation come..
DeleteHow did this equation came?
DeleteH=VIT
DeleteI=Q/T
H=V×Q/T×T
T AND T CANCEL
THEN H=VQ
Answer will be different in each case why ?it should be equal as vq =vit
DeleteAnswer is coming different
DeleteThanks for this!
ReplyDeletewhy is time multiplyed twice?
ReplyDeleteits actually ( 60 seconds in a minute x 60minutes in an hour)
DeleteThis anwer may be right but in lakhmir singh 4788.4kj is ans
ReplyDelete1200 J How????
ReplyDelete=(50×80×3600)/3
Delete3600/3= 1200
=50×80×1200j
=4800000 j
=4.8×10to the power 6 joule
Answer is same in both cases.
ReplyDeleteRight answer
ReplyDeleteBut we can do it by using vq formula