Given the standard electrode potentials Arrange these metals in their increasing order of reducing power

Q.2:Given the standard electrode potentials,

K⁺/K = −2.93V, Ag⁺/Ag = 0.80V,

Hg²⁺/Hg = 0.79V

Mg²⁺/Mg = −2.37 V, Cr³⁺/Cr = − 0.74V

Arrange these metals in their increasing order of reducing power.

Solution:

Reducing power of metals increase with decrease of reduction potential. Hence the increasing order of reducing power will

Ag < Hg < Cr < Mg < K