Q.13:How much electricity in terms of
Faraday is required to produce
(i)
20.0 g of Ca from molten CaCl2.
(ii)
40.0 g of Al from molten Al2O3.
Solution:
(i)
The balance reaction will
The charge on Ca in CaCl2
Ca + 2Cl = 0
Cl has –1 charge so that
Ca + 2(–1) =
0
Ca
= 2
We have to get 2o g Ca from Ca 2+
Number of required moles = mass / molar mass
Molar mass of Ca is 40 g/mol and
required mass of Ca is 20 g
Hence number of moles =
20/40 = 0.5 mol
Electricity required to produce 1
mol of calcium = 2 F
The electricity required to produce
0.5 mol of calcium
= 0.5 × 2 F
= 1 F
(ii)
Charge on Al in Al2O3
2Al + 3O = 0
Oxygen has –2
2Al +3(–2) = 0
Al = 3
Change transfer n = 3
Charge required for 1 mol of Al = 3F
Number of moles of Al = 40 /27
= 1.48
The electricity required to produce 1.48
mol of Al = 1.48 × 3 F
= 4.44 F
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