Q.14:
How much electricity is required in
coulomb for the oxidation of
(i)
1 mol of H2O to O2.
(ii)
1 mol of FeO to Fe2O3.
Solution:
(i)
We have 1 mol of H2O
1 mol of H2O will give
one atom of O
Charge on O = – 2
Electricity required =n F
= 2 × 96487 Coulombs
= 192974 Coulombs
= 1.93 × 105 Coulombs
(ii)
Charge on Fe in compound FeO = + 2
Charge on Fe in compound Fe2O3
= + 3
Change in charge n = 1
Electricity required =
nF
= 96487 Coulombs
= 9.65 × 104 Coulombs
It question asked at 2013 and now is 2019
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