Answer the following:
(a) You are given a thread and a metre scale. How will you estimate
the diameter of the
thread?
(b) A screw gauge has a pitch of 1.0 mm and 200 divisions on the
circular scale. Do you
think it is possible to increase the accuracy of the screw gauge
arbitrarily by increasing
the number of divisions on the circular scale?
(c) The mean diameter of a thin brass rod is to be measured by
vernier callipers. Why is
a set of 100 measurements of the diameter expected to yield a more
reliable estimate
than a set of 5 measurements only?
Solution:
(a)(a) You are given a thread and a metre scale. How will you estimate the diameter of the
thread?
Take a uniform cylindrical
smooth rod and Wrap the thread in such a way that the turns of thread are tight
and touch each immediate neighboring turns. Now measure the length of the
thread using a metre scale.
The diameter of the
thread = distance between first and last turn / number of turns
(b) A screw gauge has a pitch of 1.0 mm and 200 divisions on the circular scale. Do you
think it is possible to increase the accuracy of the screw gauge arbitrarily by increasing
the number of divisions on the circular scale?
Least count of a
screw gauge = length of pitch/number of division
Theoretically we can
increase the accuracy of screw gauge by decreasing length of pitch or increasing
number of divisions. But practically we cannot decrease length of pitch or
increase number of divisions from a contain limit. So accuracy cannot increase
from a limit.
(c)The mean diameter of a thin brass rod is to be measured by vernier callipers. Why is
a set of 100 measurements of the diameter expected to yield a more reliable estimate
than a set of 5 measurements only?
Accuracy of a measurement can be increase with
increase of number of observations hence 100 measurements is more reliable than
a set of 5 measurements.
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