In a reaction, 2A → Products, the concentration of A decreases from 0.5 mol L−1 to 0.4 mol L−1 in 10 minutes. Calculate the rate during this interval?

Answer

Given that
Initial concentration, [A1] = 0.5 mol L⁻¹
Final concentration, [A2] =0.4 mol L⁻¹
Time taken ∆t = 10 min
(In NCERT answer is in minutes so no need to convert in sec )
Average rate

Solve it we get
= 0.005 mol L⁻¹ min⁻¹
= 5 × 10⁻³ M min⁻¹

Do you know any other method of solving of problem ?
In a reaction, 2A → Products, the concentration of A decreases from 0.5 mol L⁻¹ to 0.4 mol L⁻¹ in 10 minutes. Calculate the rate during this interval?
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