Question 4.14: The half-life for radioactive decay of 14C is 5730 years. An archaeological artifact containing wood had only 80% of the 14C found in a living tree. Estimate the age of the sample.
Answer
If initial concentration [R]o =100 g
Then final concentration, [R] = 80 % of 100 = 80 g
Given that half life t1/2 = 5730 year
Use the formula
Plug the value of t ½ in this formula we get
k = 0.693/ 5730 years-1 = 1.21 x 10 -4 years -1
Use the formula of first order reaction
Plug the values in this formula we get
t = 1845 years
Answer
If initial concentration [R]o =100 g
Then final concentration, [R] = 80 % of 100 = 80 g
Given that half life t1/2 = 5730 year
Use the formula
Plug the value of t ½ in this formula we get
k = 0.693/ 5730 years-1 = 1.21 x 10 -4 years -1
Use the formula of first order reaction
Plug the values in this formula we get
t = 1845 years
Amazing site...very helpful
ReplyDeleteYess
DeleteHow are you finding the 2.303
ReplyDeleteIt is given value in formula
DeleteNice method. ..
ReplyDeleteThank u
ReplyDeleteMy excat ans is 1826
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