The rate of the chemical reaction doubles for an increase of 10 K in absolute temperature from 298 K Calculate Ea.

Answer

Given that initial temperature, T₁ = 298 K
Final temperature, T₂ = 298 + 10 = 308 K
Rate of chemical reaction will increase with raise of rate constant so that take
Initial value of rate constant k₁ = k
find rate constant, k₂ = 2k
Also, R = 8.314 J K⁻¹ mol⁻¹
Use Arrhenius equation

Here R is gas constant
Value of R = 8.314 J K⁻¹ mol⁻¹
Plug all values we get



After calculation we get
E_a = 52843 J mol⁻¹
Divide by 1000 to convert in KJ
E_a =52.8 kJ mol⁻¹
Do you know any other method of solving this problem ?
The rate of the chemical reaction doubles for an increase of 10 K in absolute temperature from 298 K. Calculate E_a.?
Please reply in below chat box and give use g+ or Like us on Facebook