**Find the intersection of each pair of sets:**

**(i) X = {1, 3, 5} Y = {1, 2, 3}**

**(ii) A = {a, e, i, o, u} B = {a, b, c}**

**(iii) A = {x: x is a natural number and multiple of 3} B = {x: x is a natural number less than 6}**

(iv) A = {x: x is a natural number and 1 < x ≤ 6} B = {x: x is a natural number and 6 < x < 10}

(iv) A = {x: x is a natural number and 1 < x ≤ 6} B = {x: x is a natural number and 6 < x < 10}

**(v) A = {1, 2, 3}, B = Φ**

**Answer**

In intersection we write common element of both sets.

**(i)**X = {1, 3, 5}, Y = {1, 2, 3} so X ∩ Y = {1, 3}

**(ii)**A = {a, e, i, o, u}, B = {a, b, c} so A ∩ B = {a}

**(iii)**Natural number and multiple of 3 are 3, 6, 9 …

Natural number less than 6 are {1, 2, 3, 4, 5, 6}

So that A ∩ B = {3}

**(iv)**) Natural numbers greater than 1 and lower than and equal to 6 are 2, 3, 4, 5 and 6.

Natural number greater than 6 and less than 10 are 7, 8 and 9.

there are no common element in both sets.

So that A ∩ B ={} or Φ

**(v)**A = {1, 2, 3}, B = Φ here B is empty or null set so there is no common element. Hence, A ∩ B = Φ

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