The conductivity of 0.20 M solution of KCl at 298 K is 0.0248 Scm−1. Calculate its molar conductivity.

Q.8:The conductivity of 0.20 M solution of KCl at 298 K is 0.0248 Scm−1. Calculate its molar conductivity.

Solution:

Given that ,

κ = 0.0248 S cm⁻¹  and c = 0.20 M

Formula of molar conductivity,

Λ_m = ( k × 1000)/M

Λ_m =(0.0248 × 1000 )/0.2

Λ_m =124 S cm² mol⁻¹