Taking the set of natural numbers as the universal set, write down the complements of the following sets:
(i) {x: x is an even natural number}
(ii) {x: x is an odd natural number}
(iii) {x: x is a positive multiple of 3}
(iv) {x: x is a prime number}
(v) {x: x is a natural number divisible by 3 and 5}
(vi) {x: x is a perfect square}
(vii) {x: x is perfect cube}
(viii) {x: x + 5 = 8}
(ix) {x: 2x + 5 = 9}
(x) {x: x ≥ 7}
(xi) {x: x ∈ N and 2x + 1 > 10}
Answer
Universal set ⇒ Set of natural numbers ⇒ {1, 2, 3, 4, 5...}
Set of even natural numbers ⇒ {2, 4, 6, 8 ...}
Set of odd natural number ⇒ {1, 3, 5...}
Set of prime number ⇒ {2, 3, 5, 7...}
(i) Complements of {x: x is an even natural number}
⇒ {1, 2, 3, 4, 5...} - {2, 4, 6, 8 ...}
⇒ {1, 3, 5...}
⇒ {x: x is an odd natural number}
(ii) Complements of {x: x is an odd natural number}
⇒ {1, 2, 3, 4, 5...} - {1, 3, 5...}
⇒ {2, 4, 6, 8 ...}
⇒ {x: x is an even natural number}
(iii) Complements of {x: x is a positive multiple of 3}
⇒ {x: x ∈ N and x is not a multiple of 3}
(iv) Complements of {x: x is a prime number}
⇒{x: x is a positive composite number and x = 1}
(v) Complements of {x: x is a natural number divisible by 3 and 5}
⇒ {x: x is a natural number that is not divisible by 3 or 5}
(vi) Complements of {x: x is a perfect square}
⇒ {x: x ∈ N and x is not a perfect square}
(vii) Complements of {x: x is a perfect cube}
⇒ {x: x ∈ N and x is not a perfect cube}
(viii){x: x + 5 = 8}
Solving the equation x + 5 ⇒ 8 we get x = 3.
Complement of this set will not have x = 3, Hence complement set can be {x: x ∈ N and x ≠ 3}
(ix){x: 2x + 5 = 9}
Solving the equation 2x + 5 = 9 we get x = 2.
Complement of this set will not have x = 2,
Hence complement set can be {x: x ∈ N and x ≠ 2}
(x) Complements of {x: x ≥ 7}
={x: x ∈ N and x < 7}
(xi) Complements of {x: x ∈ N and 2x + 1 > 10}
Solve the equation
2x + 1 > 10
2x > 9
X > 9/2
All values of x more than 9/2 cannot be in set of complement.
Hence, complements of {x: x ∈ N and 2x + 1 > 10} ⇒ {x: x ∈ N and x ≤ 9/2}
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ReplyDeleteFor the 11th question why can't we write the answer directly {1,2,3,4} as the question does not ask to be in builder form?
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