Question 6:
A copper
wire has diameter 0.5 mm and resistivity of 1.6 × 10−8 Ω m. What
will be the length of this wire to make its resistance 10 Ω? How much does the
resistance change if the diameter is doubled?
Solution:
Area of
cross-section of the wire, A =π (d/2) 2
Diameter=
0.5 mm = 0.0005 m
Resistance,
R = 10 Ω
We know
that
∴ length of the wire = 122.72m
If the diameter of the wire is
doubled, new diameter=2×0.5=1mm=0.001m
Let new resistance be Rʹ
∴ the new resistance is 2.5 Ω
They have asked that how much the resistance will change, and not what will be the resistance?
ReplyDelete1/4 times
DeleteYes..
DeleteIf the length is doubled and the diameter is reduced to half
Will the resistance change? or be same?
After finding the resistance just substract it ....or u can't even do that
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ReplyDeleteSorry but your answere is wrong it should be 1.23m.
ReplyDeleteYour mistake is at the square of 0.0005, it is 2.5.
Still thanks.
There's nothing mistake in it
DeleteYah there is no mistake
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There is a mistake while total division
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ReplyDeleteWhat will be the resistance if diameter is halved
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ReplyDeleteHow 10 minus 8 lost
ReplyDeleteThanks
ReplyDeleteThis solution wrong idiot
ReplyDeleteSorry my mistake the ans is correct im idiot
ReplyDeleteSupppe thank u for this ways u to help us
ReplyDelete