Friday 17 May 2013

A copper wire has diameter 0.5 mm and resistivity of


Question 6:
A copper wire has diameter 0.5 mm and resistivity of 1.6 × 10−8 Ω m. What will be the length of this wire to make its resistance 10 Ω? How much does the resistance change if the diameter is doubled?
Solution:
Area of cross-section of the wire, A =π (d/2) 2
Diameter= 0.5 mm = 0.0005 m
Resistance, R = 10 Ω
We know that






length of the wire = 122.72m
If the diameter of the wire is doubled, new diameter=2×0.5=1mm=0.001m
Let new resistance be Rʹ
 


the new resistance is 2.5 Ω
 

19 comments:

  1. They have asked that how much the resistance will change, and not what will be the resistance?

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    Replies
    1. Yes..
      If the length is doubled and the diameter is reduced to half
      Will the resistance change? or be same?

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    2. After finding the resistance just substract it ....or u can't even do that

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  2. This comment has been removed by the author.

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  3. Sorry but your answere is wrong it should be 1.23m.
    Your mistake is at the square of 0.0005, it is 2.5.
    Still thanks.

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  5. What will be the resistance if diameter is halved

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  8. Sorry my mistake the ans is correct im idiot

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  9. Supppe thank u for this ways u to help us

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