Wednesday, 15 May 2013

What is (a) the highest, (b) the lowest total resistance that can be secured by combinations of four coils of resistance



Question 5:
What is (a) the highest, (b) the lowest total resistance that can be secured by combinations of four coils of resistance 4 Ω, 8 Ω, 12 Ω, 24 Ω?
Solution:
Given resistances R1 =4 Ω, R2=8 Ω, R3=12Ω, and R4=24Ω.
(a) If these coils are connected in series, then the equivalent resistance will
be the highest, as R=R1+R2+R3+R4
R=4+8+12+24 = 24Ω
(b) If these coils are connected in parallel, then the equivalent resistance will be the lowest, given by

 


R=2 Ω

2 Ω is the lowest total resistance.

10 comments:

  1. This is wrong...highest should be 48 ohm ...add them and know....

    ReplyDelete
  2. It is wrong .
    Highest resistance is 48 ohm.

    ReplyDelete
  3. The highest resistance is 48 ohm

    ReplyDelete
  4. This is good you try your well but somewhere there is calculation mistake.

    ReplyDelete
  5. Highest is 48 ohm calculate carefully

    ReplyDelete