Question 5:
What is (a) the highest, (b) the lowest total resistance that can be
secured by combinations of four coils of resistance 4 Ω, 8 Ω, 12 Ω, 24 Ω?
Solution:
Given
resistances R1 =4 Ω, R2=8 Ω, R3=12Ω, and R4=24Ω.
(a) If
these coils are connected in series, then the equivalent resistance will
be the highest,
as R=R1+R2+R3+R4
∴ R=4+8+12+24 =
24Ω
(b) If these coils are connected in parallel, then the equivalent
resistance will be the lowest, given by
⇒R=2 Ω
∴ 2 Ω is the lowest total resistance.
