Method - 2
The balanced reaction of combustion of carbon can be written as:
(i) As per the balanced equation, 1 mole of carbon burns in1 mole of dioxygen (air) to
produce1 mole of carbon dioxide.
(ii) According to the question, only 16 g of dioxygen is available. Hence, it will react with
0.5 mole of carbon to give 22 g of carbon dioxide. Hence, it is a limiting reactant.
(iii) According to the question, only 16 g of dioxygen is available. It is a limiting
reactant. Thus, 16 g of dioxygen can combine with only 0.5 mole of carbon to give 22 g
of carbon dioxide.
(i) As per the balanced equation, 1 mole of carbon burns in1 mole of dioxygen (air) to
produce1 mole of carbon dioxide.
(ii) According to the question, only 16 g of dioxygen is available. Hence, it will react with
0.5 mole of carbon to give 22 g of carbon dioxide. Hence, it is a limiting reactant.
(iii) According to the question, only 16 g of dioxygen is available. It is a limiting
reactant. Thus, 16 g of dioxygen can combine with only 0.5 mole of carbon to give 22 g
of carbon dioxide.
Method - 3
Method - 4
Thank you so much...
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