Q 1.16:A
compound is formed by two elements M and N. The element N forms ccp and atoms of M occupy 1/3rd of
tetrahedral voids. What is the formula of the compound?
Solution:
Let number of atoms
of the element N = n
Number of tetrahedral voids = 2 × number of atoms in close
packaging
Therefore
Number of tetrahedral voids = 2n
It is given that the atoms of element M occupy 1/3rd of
tetrahedral voids.
So that the number of atoms of M is = (1/3) × 2n
=(2/3)n
Ratio of the number of atoms of M and N
Multiply by 3 and divide by n we get
M:N = 2:3
Hence , the formula of the compound is M2N3.
Why do we multiply by 3 at the ending?
ReplyDeletedint know the LCM
DeleteHe dont know simple maths. You don't know English.didnt
DeleteShashwat Kumar you don't know English ass well
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ReplyDeleteThanks
ReplyDeleteThis comment has been removed by the author.
ReplyDeleteTnx..
ReplyDeleteAss
ReplyDeleteWhy we multiply 3 in end
ReplyDelete