Friday, 3 May 2013

Calculate the molarity of each of the following solutions: (a) 30 g of Co(NO3)2.6H2O in 4.3 L of solution (b) 30 mL of 0.5 M H2SO4 diluted to 500 mL.


Calculate the molarity of each of the following solutions: (a) 30 g of Co(NO3)2.6H2O  in 4.3 L of solution (b) 30 mL of 0.5 M H2SO4 diluted to 500 mL.
Solution
(a)
Given that mass of Co (NO3)2.6H2O  = 30 g
Volume of solution = 4.3 liter
Molar mass of Co(NO3)2.6H2O = 59 + 2(14 + 3 × 16) + 6 (16 +1 × 2) = 291 g mol−1
Use the formula 
Moles of Co(NO3)2.6H2O = 30/291 = 0.103 mol
Use the formula 
Molarity of Co(NO3)2.6H2O = 0.103/4.3= 0.023 M

(b)
Given that
Volume of H2SO4 (V1) = 30 ml)
Diluted volume of H2SO4 (V2) = 500 ml

Number of moles present in 1000 mL of 0.5 M H2SO4 = 0.5 mol
Initial molarity M1= 0.5 M 
We have to find M2
Use the formula
M2V2 = M1V1
plug the values we get
M2  × 500  = 0.5 × 30
M2 = 15/ 500 = 0.03 M
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36 comments:

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    3. Unknown10 April 2019 at 08:05

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  4. Unknown13 March 2018 at 09:07

    Thanks

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  5. Unknown27 April 2018 at 22:01

    It is a correct answer nd well explained..

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  6. Sudip29 June 2018 at 19:42

    Nice answe.ur solution is always good

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  7. Unknown30 June 2018 at 21:41

    Thanks bro my answer is also same but in pradeep refresher and on some site answer is wrong

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  8. Unknown9 August 2018 at 02:13

    What the hell does 30 g of 0.5 M H2SO4 diluted in 500 ml mean?

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    Replies
    1. Dhriti6 April 2019 at 04:06

      Its 30ml 0.5M means molarity of solution is initially 0.5 and its volume is 30ml

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  11. Unknown11 January 2019 at 19:45

    Thanks for solution.

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  12. Manisha gupta20 January 2019 at 16:52

    Thnks

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  13. Unknown26 February 2019 at 04:36

    Thnk u for solution

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  14. Unknown12 March 2019 at 08:43

    thanks a lot for solution

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  16. yash19 March 2019 at 17:30

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  19. Unknown5 April 2019 at 07:34

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  20. Unknown7 April 2019 at 22:28

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  21. Unknown6 May 2019 at 12:12

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  22. Unknown19 May 2019 at 10:08

    It is helpful

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  23. Unknown15 June 2019 at 11:41

    Thanks sir it is helpful

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  24. Unknown4 March 2020 at 07:07

    Thanks sir

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  25. Unknown4 March 2020 at 07:08

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  26. johnsmith17 February 2026 at 05:00

    Great explanation of the molarity calculations your step by step approach makes it much easier to understand how to convert mass to moles and apply the dilution formula correctly for both parts. The breakdown of Co(NO₃)₂·6H₂O and the use of M₁V₁ = M₂V₂ were especially clear and well presented also, I really appreciate how smoothly you highlighted allpanel in your discussion it fits naturally with the topic and adds a nice, professional touch to your overall presentation.

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