The resistance of a conductivity cell containing 0.001M KCl solution at 298 K is 500M. What is the cell constant if conductivity of 0.001M KCl solution at 298 K is 0.146 × 10−3S cm−1.

Q.9:The resistance of a conductivity cell containing 0.001M KCl solution at 298 K is 500M. What is the cell constant if conductivity of 0.001M KCl solution at 298 K is 0.146 × 10⁻³S cm⁻¹.

Solution:

Given that ,

Conductivity of the cell , κ = 0.146 × 10⁻³ S cm⁻¹

Resistance of the cell , R = 1500 Ω

Formula of cell constant

Cell constant = κ × R

Plug the values we get

= 0.146 × 10⁻³ × 1500

= 0.219 cm⁻¹