Showing posts with label Find the zero of the polynomial in each of the following cases. Show all posts
Showing posts with label Find the zero of the polynomial in each of the following cases. Show all posts

Tuesday, 7 May 2013

Find the zero of the polynomial in each of the following cases

Question 4. Find the zero of the polynomial in each of the following cases:
(i) p(x) = x + 5            (ii) p(x) = x – 5           (iii) p(x) = 2x + 5        (iv) p(x) = 3x – 2
(v) p(x) = 3x               (vi) p(x) = ax, a ≠ 0    (vii) p(x) = cx + d, c ≠ 0, c, d are real numbers.

Solution: (i)p(x) = x + 5            
Plug p(x) = 0 we get
=>x+5 =0
=>  x = - 5
-5 is zero of the polynomial 

Find the zero of the polynomial in each of the following cases
(ii) p(x) = x – 5          
Plug p(x) = 0 we get
=>x - 5 = 0
=> x = 5 
5 is zero of the polynomial 

Find the zero of the polynomial in each of the following cases
(iii) p(x) = 2x + 5       
Plug p(x) = 0 we get
=>2x+5 =0
=> 2x = - 5
=> x= -5/2
-5/2is zero of the polynomial 

Find the zero of the polynomial in each of the following cases
(iv) p(x) = 3x – 2
Plug p(x) = 0 we get
=>3x-2=0
=>3x =2
=> x = 2/3
2/3 is zero of the polynomial 

Find the zero of the polynomial in each of the following cases
 (v) p(x) = 3x
Plug p(x) = 0 we get
=>3x=0
=> x= 0/3
=> x=0                       
0 is zero of the polynomial 

Find the zero of the polynomial in each of the following cases
 (vi) p(x) = ax, a ≠ 0  
Plug p(x) = 0 we get
=>ax=0
=> x =0/a
=> x = 0
0 is zero of the polynomial 

Find the zero of the polynomial in each of the following cases
 (vii) p(x) = cx + d, c ≠ 0, c, d are real numbers.
Plug p(x) = 0 we get
=>cx +d = 0
=> cx = - d
=> x = -d/c
-d/c is zero of the polynomial